What must be the specific heat of a sample of an unknown material of 36.359g, when 59.912j of heat are applied raising the temperature 152°c?

0.0108 J/g°C

We are given;

We are required to calculate the specific heat capacity of the material.

To calculate the specific heat capacity we rearrange the formula;

c = Q ÷ mΔT

  = 59.912 J ÷ (36.359 g × 152°C)

  = 0.0108 J/g°C

Therefore, the specific heat capacity of the unknown material is 0.0108 J/g°C

law of conservation of matter

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72