When two atoms with different electronegativities are bonded together, a bond_ exists. these are displayed with an arrow originating at the atom with the_ electronegativity and pointing toward the atom with the_ electronegativity. partial charges will exist on each atom when a bond exists between two atoms with different electronegativities. since the atom with a higher electronegativity will have a stronger ability to attract electrons, it will have a partial_ charge. the atom with a lower electronegativity will have an equal and opposite_ charge. as the difference in electronegativity increases, the resulting magnitudes of the partial charges will_. bond character is used to describe the severity of the electronegativity differences between the two atoms involved in a bond. bonds that have character correspond to a larger difference in electronegativities, and bond character corresponds to a smaller difference. for example, increasing the electronegativity of atom "a" in the phet simulation and decreasing the electronegativity of atom "b" will result in a bond that is_ ionic in character.

Polarity,less,more,negative,positive,increase,iso ionic

Explanation:

When two atoms with different electronegativities are bounded together a bond polarity exist.

        These are displayed wth an arrow originating at the atom with less electronegativity and pointing towards the atom with more lectronegativity.

        Since the atom with a higher electronegativity will have stronger ability to attract electron it will have a partial negative charge.The atom with lower electronegativity will have an equal and opposite positive charge.

   As the difference in the electronegativity increases the resulting magnitude of the partial charge will increase.

 For example increasing the electronegativity of atom A in the phet stimulation and decreasing the electronegativity of atom B will result in a bond that iso ionic in character.

the answer for sodium is 0.186

the answer for rubidium is 0.251

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol