The henry's law constant for helium gas in water at 30c is3.70x10-4 m/atm. when the partial pressure ofhelium above a sample of water is 0.650 atm, the concentration ofhelium in the water .

a. 2.41 x 10-4
b. 3.70 x 10-4
c. 1.76 x 103
d. 5.69 x10-4
e. 1.30

a. S = 2.41 x 10⁻⁴ M

Explanation:

The solubility S of a gas in water at a given temperature  is given by the equation

S = Kp where S= solubility of the gas

                       K= Henry's Constant for the gas

                       p = partial pressure of the gas

solving for S

S = 3.70 x 10⁻⁴ M/atm x 0.650 atm =2.41 x 10⁻⁴ M

sry but any answer choices

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