Chemistry, 11.11.2019 23:31 21hendlill
Lead ions can be precipitated from solution with kcl according to the following reaction:
pb2+(aq) + 2kcl(aq) --> pbcl2(s) + 2k+(aq)
when 28.8g kcl is added to a solution containing 25.6g pb2+, a pbcl2 precipitate forms. the precipitate is filtered and dried and found to have a mass of 29.6g.
determine the theoretical yield of pbcl2.
m=
determine the percent yield for the reaction.
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Lead ions can be precipitated from solution with kcl according to the following reaction:
pb2...
pb2...
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