What is the nh brickell formula of a compound that contains 3.609 g calcium and 6.384 g chlorine by mass

CaCl₂

Explanation:

Given data:

Mass of calcium = 3.609 g

Mass of chlorine = 6.384 g

Empirical formula = ?

Solution:

Number of moles of calcium:

Number of moles of calcium = mass/ molar mass

Number of moles of calcium = 3.609 g/ 40 g/mol

Number of moles of calcium = 0.090 mol

Number of moles of chlorine:

Number of moles of chlorine = mass/ molar mass

Number of moles of chlorine = 6.384 g/ 35.5 g/mol

Number of moles of chlorine = 0.18 mol

                    Ca                 :               Cl

            0.090/0.090        :               0.18/ 0.090

                      1                   :               2

Empirical formula:

CaCl₂

the answer to your question is c

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.