A) the lab tech called in sick today and you are called in to prepare
750.0 mls of 2.00 m k3po4 (212.27 g/mol) solution. what mass of k3po4
should you weigh out?

318.405 g

We are given;

We are required to determine the mass of K₃PO₄ to be measured.

Molarity = Moles ÷ Volume

Rearranging the formula;

Number of moles = Molarity × Volume

Therefore;

Moles of K₃PO₄ = 2.00 M × 0.75 L

                          = 1.5 moles

Mass = Number of moles × Molar mass

Molar mass of K₃PO₄ = 212.27 g/mol

Therefore;

Mass of K₃PO₄ = 1.5 moles × 212.27 g/mol

                        = 318.405 g

Therefore, the mass of K₃PO₄ that should be weighed is 318.405 g

the atomic mass is the bottom number on the element.

-steel jelly