You will use a large excess of fe+3 ion, which will drive the reaction to completion. thus, you can assume that the final fescn+2 concentration is equal to the concentration of kscn added, as the kscn is the limiting reagent, in the total volume of the solution. you must test each solution as it is made; therefore, you must plan out ahead of time with your partner how you will accomplish this in an organized and expedient way.

The answer is b because c don't explain why the moths are on them and it isn't a because as we know only one species of moth does this

Answerhund's rule;

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.