Consider the reaction of zinc sulfide and oxygen:
2 zns (s) + 3 o2 (g) → 2 zno (s) + 2 so2 (g)
what is the maximum mass of zinc oxide that can be produced by the reaction of 46.32 g of zinc sulfide and 15.5172 g of oxygen?
feel free to round the given mass values to 4 significant figures.
your answer must include the units. the tolerance is not part of the answer.
numeric response

Mass = 0.004 g

Explanation:

Given data:

Mass of zinc sulfide = 46.32 g

Mass of oxygen = 15.5172 g

Mass of zinc oxide = ?

Solution:

Chemical equation:

2ZnS + 3O₂ → 2ZnO + 2SO₂

Number of moles of ZnS:

Number of moles = mass/ molar mass

Number of moles =  46.32 g/ 97.5 g/mol

Number of moles = 0.46 mol

Number of moles of Oxygen:

Number of moles = mass/ molar mass

Number of moles =  15.5172 g/ 32 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.

                            ZnS        :       ZnO

                               2          :          2

                             0.46       :         0.46

                             O₂          :          ZnO

                             3            :            2

                             0.48       :           2/3×0.48 =0.32 mol

The number of moles of zinc oxide produced by oxygen are less so it will limiting reactant.

Mass of zinc oxide:

Mass = number of moles / molar mass

Mass = 0.32 mol / 81.38 g/mol

Mass = 0.004 g

i think it is true since you can test the answer and can use observations to complete it.

pv=nrt

explanation: