The oxidation of glucose can result in several products. you perform combustion analysis on a 2.750 g sample that resulted from the oxidation of glucose and obtain 3.702 g co2 and 1.514 g h2o. how many carbon atoms are in the empirical formula of the isolated sample? (assume no other products present from the oxidation of glucose.)]

There is 1 carbon atom in the empirical formula.

Explanation:

First, let's use the given mass of CO₂ to calculate the moles of C, which will be the same amount of C moles present in the sample:

Then with the mass of H₂O we calculate the moles of H:

Now we calculate the mass of C, H in the sample, in order to calculate the mass of O, which is calculated by substracting the mass of C and H from the total mass:

Then we convert g O to mol O

C ⇒ 0.0841 mol C

H ⇒ 0.1682 mol H

O ⇒ 0.0983 mol O

Now we divide those values by the lowest among them:

So the empirical formula is CH₂O

There is 1 carbon atom in the empirical formula.

the answer is c

tell me if wrong

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;