Identify the oxidation numbers for all the elements in the reactants and products for 4h2o2(aq)+cl2o7(g)+2oh−(aq)→2clo2−( aq)+5h2o(l)+4o2(g) identify the oxidation numbers by dragging the appropriate labels to their respective targets. -7-7 -5-5 -4-4 -3-3 -2-2 -1-1 00 +1+1 +2+2 +3+3 +4+4 +5+5 +7+7

H₂O₂: H (+1); O (-1)

Cl₂O₇: Cl (+7); O (-2)

OH⁻: O (-2); H (+1)

ClO₂⁻: Cl (+3); O (-2)

H₂O:  H (+1); O (-2)

O₂: O (0)

Explanation:

The oxidation number (o.n.) is the number of electrons an atom tends to gain or lose to form a chemical bond and gain stability.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

possibly, yes.

explanation:

the amount of sugar you take in is dangerously high, risk of heart disease, high risk of diabetes, and etc.