Arigid cylinder with a movable piston contains a sample of hydrogen gas. at 330. k, this sample has a pressure of 150. kpa and a volume of 3.50 l. what is the volume of this sample at stp?

V₂ = 4.34 L

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 3.50 L

Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)

Initial temperature = 330 K

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ =  1.5 atm ×  3.50 L × 273 K / 330 K × 1 atm

V₂ = 1433.3 atm .L. K / 330 k.atm

V₂ = 4.34 L

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error