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Chemistry, 14.11.2019 05:31 gameranonymous266

A25.00 ml sample containing an unknown amount of al3+ and pb2+ required 17.14 ml of 0.04907 m edta to reach the end point. a 50.00 ml sample of the unknown was then treated with f− to mask the al3+ . to the 50.00 ml sample, 25.00 ml of 0.04907 m edta was added. the excess edta was then titrated with 0.02064 m mn2+ . a total of 26.5 ml was required to reach the methylthymol blue end point. determine pal3+ and ppb2+ in the unknown sample.

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A25.00 ml sample containing an unknown amount of al3+ and pb2+ required 17.14 ml of 0.04907 m edta t...
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