What volume of a 4.5 m solution of phosphate is necessary to create a 80.0 ml stock of 2.0 m phosphate solution?

V1 = 45.6 ml

Explanation:

This is a dilution process whereby the concentration of phosphate in the solution is being reduced from 4.5m to 2m. Meanwhile. In a concentration process, the concentration of the phosphate solution will be increased. It can be achieved by removing solvents.

The dilution equation will be used. The equation is as follows:

M1V1 = M2V2 where

V1 = Initial volume of phosphate solution.

M1 = Initial concentration of phosphate solution.

V2 =Final volume of phosphate solution.

M2 = Final concentration of phosphate solution .

From the information given,

M1 = 4.5

V1 = ?

M2 = 2.0

V2 = 80

4.5 × V1 = 2×80

4.5V1 = 160

V1 = 160/4.5

= 35.6 ml

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).