If you dissolve 24.4 g of nacl in 251 g of water and generate a solution that has a density of 1.10 g/ml, what is the molarity of nacl in this solution? enter a numerical value in the correct number of significant figures. do not enter units in the answer box, but understand that the unit needed for the final answer is m.

The molarity of this NaCL solution is 1.83 M:

Explication:

Step 1: Data  given

Mass of NaCl = 24.4 grams

Mass of water = 251 grams

Density of water = 1.10 g/mL

Step 2: Calculate volume of water

Volume of water = Mass of water / density of water

Volume of water = 251 grams / 1.10 g/mL

Volume of water = 228.18 mL =0.22818L

Step 3: Calculate moles NaCl

Number of moles NaCl = 24.4 grams / 58.44 g/mol

Number of moles = 0.4175 moles

Step 4: Molarity of the solution

Molarity = Number of moles / Volume

Molarity = 0.4175 moles / 0.22818 L

Molarity = 1.83 M

The molarity of this NaCL solution is 1.83 M

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied