How many atoms are there in 10200ml of mustard gas (cl^2) at rtp?

3.84 × 10^24 atoms

We are given;

Volume of mustard gas = 10200 mL

We are required to calculate the number of atoms.

Note that one mole of  a gas occupies a volume of 24 L or 24000 mL at RTP.

Therefore, we can determine the number of moles of mustard gas;

Moles = Volume ÷ Molar gas volume (RTP)

          = 10200 mL ÷ 24000 mL/mol

          = 0.425 moles

But, 1 mole of a gas molecule contains a number of molecules equivalent to the Avogadro's number, 6.022 × 10^23.

Thus;

1 mole of Mustard gas = 6.022 × 10^23 molecules

Thus, we can determine the number of molecules of mustard gas;

Number of molecules = Moles × Avogadro's number

                                    = 0.425 moles × 6.022 × 10^23 molecules/mole

                                    = 2.56 × 10^23 molecules

We are required to determine the number of atoms.

Mustard gas has a chemical formula of C4H8Cl2S

Therefore, 1 molecule of mustard gas = 15 atoms

Thus, we can calculate the number of atoms;

Number of atoms = Molecules × Atoms/molecule

                             = 2.56 × 10^23 molecules × 15 atoms/molecule

                             = 3.84 × 10^24 atoms

Therefore, 10200 ml of mustard gas contains 3.84 × 10^24 atoms

metric time was an attempt to create a standard unit of time based off of 10, but it never took off an is not included in the metric system (si)

the correct answer would be b) volume versus temperature, because they are also directly proportional.