An element x has two naturally occurring isotopes: x-35 (abundance = 75.77%, mass = 34.968852 amu) and x-37 (abundance = 24.23%, mass = 36.965903 amu).

calculate the weighted atomic mass of x. also, identify the unknown element.

a) 39.948 amu argon
b) 35.453 amu chlorine
c) 79.904 amu bromine
d) 32.066 amu sulfur

x = 35.453 amu.  CHLORINE

Explanation:

Abundance of X³⁵ = 75.77%

Abundance of X³⁷ = 24.23%

Atomic mass of X³⁵ = 34.968852 amu

Atomic mass of X³⁷ = 36.965903 amu

Average atomic mass = ?

Solution:

Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass of carbon = (34.968852 × 75.77)+(36.965903 ×24.23) /100

Average atomic mass of carbon=  2649.59 + 895.684 / 100

Average atomic mass of carbon = 3545.274 / 100

Average atomic mass of carbon = 35.453 amu.

x = 35.453 amu.  CHLORINE

b. is the answer hoped i        

each chemical family is represented as a group or column on the periodic table. based on chemical properties, there are 6 types of chemical families. group 1 represents alkali metals, group 2 represents alkaline earth metals, groups 3 to 12 represent transition metals, groups 13 to 16 represent non-metals and other metals, group 17 represents halogens and group 18 represents noble gases.