Identify the oxidizing agent and the reducing agent for 4li(s) + o_2 (g) to 2li_2o(s).

The reaction is:

4Li(s) + O2 (g) = 2Li+  + 2O-2(s).

The oxidizing agent is the one that is being reduced which is oxygen  where the charge changed from neutral to -2 while the reducing agent is the on being oxidized which is lithium where the charge change from neutral to +1.

Ithink this is what you meant. the temperature at which a liquid begins to boil is called the boiling point. the boiling point of water is 212°f or 100°c.  and at that point will start to turn into steam (gas)