In the activity, click on the e∘cell and keq quantities to observe how they are related. use this relation to calculate keq for the following redox reaction that occurs in an electrochemical cell having two electrodes: a cathode and an anode. the two half-reactions that occur in the cell are cu2+(aq)+2e−→cu(s) and fe(s)→fe2+(aq)+2e− the net reaction is cu2+(aq)+fe(s)→cu(s)+fe2+(aq) use the given standard reduction potentials in your calculation as appropriate.

The standard cell potential of the reaction is 0.78 Volts.

Explanation:

Reduction at cathode :

Reduction potential of   to Cu=

Oxidation at anode:

Reduction potential of   to Fe=

To calculate the of the reaction, we use the equation:

Putting values in above equation, we get:

The standard cell potential of the reaction is 0.78 Volts.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.