Consider a box with two gases separated by an impermeable membrane. the membrane can move back and forth, but the gases cannot penetrate the membrane. the left side is filled with gas a and the right side is filled with gas b. we will assume that equipartition applies to both gases, but gas a has an excluded volume due to large molecules so its entropy has a different formula. sa=nakln(va? bna)+f(ua, na)sb=nbkln(vb)+f(ub, nb)keep in mind that the total box volume is constant, so va+vb=constantva+vb=constant. if na= 1 moles, nb = 2 moles, the total volume of the box is 1 m3, and b= 4 × 10-4 m3/mole, then find the equilibrium value of va by maximizing the total entropy.