How many grams of fe3o4 are required to react completely with 300 grams of h2? fe3o4 + h2=fe + h2o

8613.5 g

Explanation:

The formula for the calculation of moles is shown below:

For

Mass of  = 300 g

Molar mass of  = 2.016 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the given reaction:

4 moles of will react 1 mole of

1 mole  of will react 1/4 mole of

148.81 moles of will react 148.81/4 mole of

Moles of required = 37.2025 mol

Molar mass of = 231.53 g/mol

Mass of = Moles × Molar mass = 37.2025 × 231.53 g = 8613.5 g

8596 g of is present

Explanation:

Given the equation is

On balancing the equation, we get,

So, 1 mole of reacts with 4 moles of

Therefore the ratio is 1:4

Moles of used in the reaction = 300/0.02 = 148.5 moles

present in the reaction =

Therefore, 8596 g of is present

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.