Athermos contains 150 cm3 of coffee at 85 . to cool the coffee, you drop two 11-g ice cubes into the thermos. the ice cubes are initially at 0 and melt completely. what is the final temperature of the coffee? treat the coffee as if it were water.

73.73°C is the final temperature of the coffee.

Explanation:

Heat lost by the coffee = Q

Mass of the coffee = m

Volume of coffee = V =

Density of water = Density of coffee solution = d = 1 g/mL (given)

Heat capacity of the coffee is equal to that of water= c = 4.18 J/g°C

Initial temperature of the coffee =

Final temperature of the coffee = T

Heat required to melt 11 grams of melt ice = Q'

Latent heat of ice =

Heat absorbed by the ice after melting = q

Mass of ice melted into water = m' = 11 g

Heat capacity of water = c = 4.18 J/g°C

Initial temperature of water = = 0°C

Final temperature of water = T

According law of conservation of energy , energy lost by coffee will equal to heat required to melt ice and further to raise the temperature of water.

On solving we get:

T = 73.73°C

73.73°C is the final temperature of the coffee.

the answer to your question is c.

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the answer is 303.15 or 303