Acell composed of a platinum indicator electrode and a silver-silver chloride reference electrode in a solution containing both and has a cell potential of v. if the silver-silver chloride electrode is replaced with a saturated calomel electrode (sce), what is the new cell potential?

Explanation:

Let us assume that the solution contains both and which has a cell voltage of 0.719 V.

Therefore, voltage of cell contains both Ag/AgCl reference electrode where electrode is 0.719 V.

As, = 0.719 V

It is known that potential of the silver-silver chloride reference electrode is 0.197 V.

Hence, = 0.197 V. Now, calculate as follows.

            = 0.719 V

            = 0.719 V

            = 0.916 V

Now, voltage of the cell that contains both calomel reference electrode and electrode as follows.

= calomel electrode = 0.241 V  

           Voltage of cell =

                                     = 0.916 V - 0.241 V

                                     = 0.675 V

Thus, we can conclude that 0.675 V is the new voltage.

it should be all of them because it asks if you included all of those in your answer

explanation:

that's what i got you can count the number of atoms