35.0 ml of acid with an unknown concentration is titrated with 24.6 ml of 0.432 m base. what is the concentration of the acid? assume the acid contributes 1 mole of (h+) ions/mole of acid and the base contributes 1 mole of (oh-) ions/mole of base.

3.29 m
0.615 m
0.304 m

Given:

35.0 mL of acid with an unknown concentration

24.6 mL of 0.432 M base

Required:

Concentration of the acid

Solution:

M1V1 = M2V2

M1 (35.0 mL of acid) = (0.432 M base) (24.6 mL of base)

V1 = (0.432 M base) (24.6 mL of base) / (35.0 mL of acid)

M1 = 0.304 M of acid

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

subscribe to my yt channel yoongi jmz

follow my insta yoongi_jams

stan bts

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.