A237.0 g sample of molybdenum metal is heated to 100.10 °c and then dropped into an insulated cup containing 244.0 g of water at 10.00 °c. if the final temperature of the water and metal in the cup is 15.30 °c, then what is the specific heat of molybdenum? (specific heat of water = 4.186 j/g-°c do not add the unit in the answer.

Answer : The specific heat of molybdenum metal is,

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

where,

= specific heat of molybdenum metal = ?

= specific heat of water =

= mass of molybdenum metal = 237.0 g

= mass of water = 244.0 g

= final temperature of water and metal =

= initial temperature of molybdenum metal =

= initial temperature of water =

Now put all the given values in the above formula, we get

Therefore, the specific heat of molybdenum metal is,

the ratio of the conjugate base to the acid required to attain the desired ph.