The concentration of copper(ii) sulfate in one brand of soluble plant fertilizer is 0.07% by mass. if a 20 g sample of this fertilizer is dissolved in 2.0 l of solution, what is the molarity of cu2+?

The molarity of ions in the given amount of sample is

Explanation:

We are given:

Mass of sample = 20 g

0.07 % (m/m) of copper (II) sulfate in plant fertilizer

This means that, in 100 g of plant fertilizer, 0.07 g of copper (II) sulfate is present

So, in 20 g of plant fertilizer, = of copper (II) sulfate is present.

To calculate the molarity of solution, we use the equation:

We are given:

Mass of solute (copper (II) sulfate) = 0.014 g

Molar mass of copper (II) sulfate = 159.6 g/mol

Volume of solution = 2.0 L

Putting values in above equation, we get:

The chemical equation for the ionization of copper (II) sulfate follows:

1 mole of copper (II) sulfate produces 1 mole of copper (II) ions and sulfate ions

Molarity of copper (II) ions =

Hence, the molarity of ions in the given amount of sample is

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.