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Chemistry, 22.11.2019 01:31 mihir50

Given the following heats of combustion. ch3oh(l) + 3/2 o2(g) co2(g) + 2 h2o(l) δh°rxn = -726.4 kj c(graphite) + o2(g) co2(g) δh°rxn = -393.5 kj h2(g) + 1/2 o2(g) h2o(l) δh°rxn = -285.8 kj calculate the enthalpy of formation of methanol (ch3oh) from its elements.

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Given the following heats of combustion. ch3oh(l) + 3/2 o2(g) co2(g) + 2 h2o(l) δh°rxn = -726.4 kj c...
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