How many miles of ammonia are need to produce 45.5 grams of water

1.69 moles of ammonia are needed to produced 45.5 g of water.

Explanation:

Given data:

Mass of water = 45.5 g

Moles of ammonia required = ?

Solution:

Chemical equation:

4NH₃ + 5O₂ → 4NO + 6H₂O

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles =   45.5 g/ 18 g/mol

Number of moles = 2.53 mol

Now we will compare the moles of water with ammonia.

                         H₂O                :           NH₃

                            6                 :              4

                        2.53                :              4/6×2.53 = 1.69 mol

1.69 moles of ammonia are needed to produced 45.5 g of water.

the answer is true.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"