Derive the net ionic equation for the reaction between sodium alginate and cacl2

i’m having a hard time pls

2NaC₆H₇O₆ + CaCl₂ -> 2NaCl + Ca(C₆H₇O₆)₂

C₆H₇O₆⁻ + Cl⁻ -> Cl⁻ + C₆H₇O₆⁻

Explanation:

Here the reaction which is taking place is a double displacement reaction.

In this there is only an exchange of bonds and no chemical reaction.

Here the ions remain exactly the same

C₆H₇O₆⁻ + Cl⁻ -> Cl⁻ + C₆H₇O₆⁻

We can balance the skeletal equation

NaC₆H₇O₆ + CaCl₂ -> NaCl + Ca(C₆H₇O₆)₂

First we balance Chlorine atoms by writing 2NaCl

NaC₆H₇O₆ + CaCl₂ -> 2NaCl + Ca(C₆H₇O₆)₂

Now in order to balance Na atoms we make it 2NaC₆H₇O₆

2NaC₆H₇O₆ + CaCl₂ -> 2NaCl + Ca(C₆H₇O₆)₂

In this equation all atoms are balanced.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

the answer would be a