The solution in the arms of a u-tube are separated at the bottom of the tube by a selectively permeable membrane. the membrane is permeable to sodium chloride but not to glucose.
side a is filled with a solution of 0.4 mols of glucose and 0.5 mols of sodium chloride (nacl), and side b is filled with the a solution containing 0.8 mols of glucose and 0.4 mols of sodium chloride. initially, the volume in both arms is the same.
a. initially at the sun of the experiment, which of the following is true?
a. side a is hypertonic to side b
b. side a is hypotonic to side b
c. side a is hypertonic to side b with respect to glucose
d. side a is hypotonic to side b with respect to nacl
b. after diffusion and equilibrium:
how many mols of glucose are on side a? side b?
how many mols of nacl are on side a? side b?
c. if you examine side a after three days you should find
a. a decrease in the number of mols of nacl and glucose and an increase in the water level
b. a decrease in the number of mols of nacl and a decrease in the water level
c. a decrease in the number of mols of nacl, an increase in water level, and no change in the number of mols of glucose

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A) the enthralling of formation for pure element in its standard state is always positivehope this : )

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.