Only 10 mole of water will react with 10 mole of Na metal
and produce
10 moles of NaOH5 moles of H₂ gasHeat
10Na + 10H₂O > 10NaOH + 5H₂
Explanation:
2Na + 2H₂O > 2NaOH + H₂
Exothermic Reaction:
This reaction is supper exothermic and when sodium metal react with water it produce a lot of heat.
Limiting Reagent:
Limiting reagent is the amount of reactant in a chemical reaction that determines the amount of products that will be produce.
For instance we will use the same equation
2Na + 2H₂O > 2NaOH + H₂
The reaction shows that 2 mole of sodium combine with 2 mole of water and will produce 2 mole of NaOH and 1 mole of Hydrogen gas.
if we increase the amount of water to 4 mole then the same amount of product will form, and the extra water will remain unracted.
Similarly if we increase amount of Na to 4 mole then only 2 mole will react and will produce same amount.
Now
if we add 10 mole of Na to a large Volume of water following thing will happen
only that amount of water will be used that requires for 10 mol of NaThe extra water will remain unreactedNaOH will producedHydrogen gas will evolve
Given Reaction:
2Na + 2H₂O > 2NaOH + H₂
Data from Reaction:
2Na + 2H₂O > 2NaOH + H₂
2 mole 2mole 2mole 1mole
Applying unity formula:
2 mole of Na will react with 2mole of water
So
2 mole of Na ≅ 2mole of H₂O
10 mole of Na = 10 mole of H₂O
So the same reaction will occur and produce NaOH and hydrogen gas
So, From the above reaction
2 mole of Na ≅ 2mole of NaOH
if 2 mole of Na produces 2 mole of NaOH then 10 mole will produce how much NaOH
apply the unity formula
2 mole of the Na ≅ 2 mole of NaOH
10 mole of the Na ≅ X mole of NaOH
so by cross multiplication
2 mole of Na x X mole of NaOH ≅ 2 mole of NaOH x 10 mole of the Na
we have to find moles of NaOH so by rearrangement of the above equation
X mole of NaOH = 2 mole x 10 mole
2 mole
X mole of NaOH= 10 mole
So
10 mole of Na will produce 10 mole NaOH
For Hydrogen Gas that produce :
2 mole of Na ≅ 1 mole H₂
If 2 mole of Na produces 1 mole of H₂ then 10 mole will produce how much H₂
apply the unity formula
2 mole of the Na ≅ 1 mole of H₂
10 mole of the Na ≅ X mole of H₂
so by cross multiplication
2 mole of Na x X mole of H₂ ≅ 1 mole of H₂ x 10 mole of the Na
we have to find moles of H₂ so by rearrangement of the above equation
X mole of H₂ = 1 mole x 10 mole
2 mole
X mole of H₂ = 5 mole
So
The following will be reaction if 10 moles Na thrown in large volume of water
Only 10 mole of water will react with it
10Na + 10H₂O > 10NaOH + 5H₂ and heat