In the hall-heroult process, a large electric current is passed through a solution of aluminum oxide (al2o3) dissolved in molten cryolite , resulting in the reduction of the to pure aluminum. suppose a current of 690. a is passed through a hall-heroult cell for 46. seconds. calculate the mass of pure aluminum produced.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :