vinegar is a solution ofacetic acid, ch3cooh, dissolved in water. a 5.54-gsample of vinegar was neutralized by 30.10 ml of 0.100 m naoh. whatis the percent by weight of acetic acid in the vinegar?

why is the answer3.26%?

The mass percentage is 3.26 %.

Explanation:

The reaction between acetic acid and NaOH will be:

Thus one mole of acetic acid will react with one mole of NaOH.

The moles of NaOH used = molarity X volume = 0.1 X 30.10 mL = 3.010 mmol

The moles of acetic acid reacted = 3.010 mmol

The moles of acetic acid will be used to calculate the mass of acetic acid used

Mass of acetic acid used = moles X molar mass = 3.010mmol X 60

mass of acetic acid used = 180.6 mg = 0.1806 g

The mass of vinegar used = 5.54 g

The percentage of acetic acid in vinegar will be =%

quartz

explanation:

it is the most commonly accepted one