The volume of a gas is 250ml at 3.6 atm. what will the volume be when the pressure is reduced to 0.75 atm?

V₂ =  1200 mL

Explanation:

Given data:

Volume of gas = 250 mL

Pressure of gas = 3.6 atm

Final pressure = 0.75 atm

Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ /P₂

V₂ = 3.6 atm . 250 mL /0.75 atm

V₂ = 900 atm. mL /0.75 atm

V₂ =  1200 mL

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the answer for sodium is 0.186

the answer for rubidium is 0.251