Acylinder with a moveable piston contains 92g of nitrogen. the external pressure is constant at 1.00 atm. the initial temperature is 200k. when the temperature is increased by 83 k, by taking it out of the freezer, the volume will increase, according to the ideal gas law. calculate the work for this process. express your answer in j.

The work for the given process is (- 2263.4 J)

Explanation:

Given: Mass of nitrogen gas (N₂): w = 92 g, external pressure: P = 1 atm, Initial temperature: T₁ = 200 K, Final temperature: T₂ = 200 + 83 K = 283 K

Molar mass of N₂ gas: m = 28 g, Gas constant: R = 8.314 J.K⁻¹.mol⁻¹

The number of moles of N₂ gas = w ÷ m = 92 g ÷ 28 g/mol = 3.28 mole

To find the initial volume (V₁) and final volume (V₂), we use the ideal gas equation:

So the Work:  

Therefore, the work for the given process: W = (- 2263.4 J)

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

plz give brainliest

12 is it do you think so