In part d of the experiment, a student begins with a beaker containing 10.0 ml of 0.010 m hcl solution and adds different volumes of 0.010 m naoh. (a) how many millimoles of acid are initially in the beaker? (if in doubt, look back at your calculation from experiment 9).

There are initially 0.1 millimoles of acid (HCl) in the beaker.

Explanation:

Step 1: Data given

volume of 0.010 M HCl = 10.0 mL = 0.01 L

Step 2: Calculate the number of moles HCl

Number of moles =  Molarity HCl * volume of solution

Number of moles HCl = 0.010 M * 0.01 L = 0.0001 moles HCl = 0.1 *10^-3 mol = 0.1 mmol HCl

There are initially 0.1 millimoles of acid (HCl) in the beaker.

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