To what temperature in kelvin will a 2.3 l balloon have to be heated to expand to a volume of 400 l assume the initial temperature of the balloon is 25 degrees celsius.

T₂ = 51826.1 K

Explanation:

Given data:

Initial Volume = 2.3 L

Final volume = 400 L

Initial temperature = 25 °C (25+ 273 = 298 K)

Final temperature = ?

Solution:

V₁/T₁ = V₂/T₂

T₂ = V₂ T₁/V₁

T₂ =  400 L . 298 K / 2.3 L

T₂ = 119200 K. L / 2.3 L

T₂ = 51826.1 K

the product of the pressure and volume is also constant

2b2t

explanation:

2b2t