For the reaction, calculate how many grams of the product form when 14.4 g of br2 completely reacts. assume that there is more than enough of the other reactant. 2k(s)+br2(l)→2kbr(s)

The answer to your question is 21.45 g of KBr

Explanation:

Chemical reaction

                               2K + Br₂   ⇒   2KBr

                                       14.4            ?

Process

1.- Calculate the molecular mass of bromine and potassium bromide

Bromine = 2 x 79.9 = 159.8g

Potassium bromide = 2(79.9 + 39.1) = 238 g

2.- Solve it using proportions

              159.8 g of Bromine 238 g of potassium bromide                    

                14.4 g of Bromine    x

                        x = (14.4 x 238) / 159.8

                        x = 3427.2 / 159.8

                        x = 21.45g of KBr