What problem would arise if the excess acetyl‑coa were not converted to ketone bodies?

a. although acetyl‑coa is not toxic, it inhibits d‑β‑hydroxyacyl‑coa dehydrogenase.
b. although acetyl‑coa is not toxic, it prevents transfer of fatty acids into the mitochondria by forming acetyl carnitine.
c. fatty acid oxidation would stop when all of the coa is bound as acetyl‑coa.
d. formation of acetyl‑coa requires uptake of a proton, and the increased ph inhibits further oxidation.

The correct answer is C fatty acid oxidation would stop when all of the CoA is bound as acetyl CoA.

Explanation:

Acetyl CoA is the principle end product of beta oxidation of even chain fatty acid such as palmitic acid.

    When the cellelar label of actyl CoA increases at that time the excess acetyl CoA is converted to ketone bodies by the process called ketogenesis.

 According to the question if the excess acetyl CoA is not converted to ketone bodies then it will interfere with the oxidation of fatty acid because fatty acid molecules will not get any CoA SH molecule to activate themselves to initiate a new round of beta oxidation.

As a result fatty acid oxidation will stop.

the answer to your question is c

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml