Aspirin (acetylsalicylic acid, c9h8o4) is a weak monoprotic acid. to determine its acid-dissociation constant, a student dissolved 2.00 g of aspirin in 0.600 l of water and measured the ph. what was the ka value calculated by the student if theph of the solution was 2.62? a 0.100 m solution of ethylamine (c2h5nh2) has a ph of 11.87. calculate the kb for ethylamine.

Explanation:

We have to start with the calculation of the concentration of the acid, using the molar mass:

Molas mass of = 180.16 g/mol

The,  with the ionization equation for aspirin, using the ICE table, we can calculate the Ka expression.

            HA     <=>    A^-      +      H^+

I       0.019             Zero            Zero

C           -X               +X               +X

E     0.019-X              X                  X

Now, we can calculate X using the pH value:

With this value we can calculate the Ka, so:

.

For the ethylamine we have to follow the same procedure:

         B^-    +    H2O     <=>    BH      +      OH^-

I          0.1              /                  Zero            Zero

C           -X            /                   +X               +X

E          0.1-X          /                    X                  X

Now, we can calculate X using the pH value:

With this value we can calculate the Kb, so:

the answer is either b or c

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.