Sulfur dioxide, so2(g), can react with oxygen to produce sulfur trioxide, so3(g), by the following reaction
2so2+o2=2so3

the standard enthalpies of formation for so2(g) and so3(g) are
deltah= so2(g)= -296.8 kj
dh= so3(g)= -395.7 kj
calculate the amount of energy in the form of heat that is produced when a volume of 3.75 l of so2(g) is converted to 3.75 l of so3(g) according to this process at a constant pressure and temperature of 1.00 atm and 25.0

The heat produced is -15,1kJ

Explanation:

For the reaction:

2SO₂+O₂ → 2SO₃

The enthalpy of reaction is:

ΔHr = 2ΔHf SO₃ - 2ΔHf SO₂

As ΔHf SO₃ = -395,7kJ and ΔHf SO₂ = -296,8kJ

ΔHr = -197,8kJ

Using n=PV/RT, the moles of reaction are:

= 0,153 moles of reaction

As 2 moles of reaction produce -197,8kJ of heat, 0,153moles produce:

0,153mol× = -15,1kJ

I hope it helps!

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.