A17.55 ml solution of potassium nitrate (kno3) was diluted to 125.0 ml, and 25.00 ml of this solution was then diluted to 1.000 × 103 ml. the concentration of the final solution is 0.00383 m. calculate the concentration of the original solution.

Explanation:

Given data:

V1 = 25.0 ml

M2 = 0.00383 M

V2 = 1000 ml

we knwo that

    ∴

               = 0.1532 M

0.1532 M is concentration in 25 ml but taken from 125 ml solution.

  ∴ The concentration in 125.0 ml solution is = 0.1532 M

M1 = 0.1532 M

V1 = 125.0ml and          V2 = 17.5.0ml

the dissolution of polymer can be thermodynamically described in 2 steps.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.