Aballoon at 30.0°c has a volume of 222 ml. if the temperature is increased to 56.1°c and the pressure remains constant, what will the new volume be, in ml?

V₂ ≈ 241 mL

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Equality Properties

Chemistry

Unit 0

Temperature Conversion: K = °C + 273.15

Gas Laws

Charles' Law:

V is volumeT is temperature (in Kelvins)Explanation:

Step 1: Define

V₁ = 222 mL

T₁ = 30.0 °C

T₂ = 56.1 °C

Step 2: Identify Conversions

Temp Conversion

Step 3: Convert

T₁ - 30.0 °C + 273.15 = 303.15 K

T₂ - 56.1 °C + 273.15 = 329.25 K

Step 4: Solve for V₂

Substitute [CL]:                    Cross-multiply:                    Isolate V₂:                            Rewrite:                              

Step 5: Check

We are given 3 sig figs. Follow sig fig rules and round.

241.113 mL ≈ 241 mL

There is one s orbital, and there are three p orbitals, five d orbitals, and seven f orbitals. thus, the answer is b. do not confuse the number of orbitals in a subshell with the number of electrons the subshell can hold. each orbital can hold two electrons, so the capacity of an nf subshell is 14 electrons.

Ithink this is what you meant. the temperature at which a liquid begins to boil is called the boiling point. the boiling point of water is 212°f or 100°c.  and at that point will start to turn into steam (gas)