Calcium chloride, cacl2, is commonly used as an electrolyte in sports drinks and other beverages, including bottled water. a solution is made by adding 6.50 g of cacl2 to 60.0 ml of water at 25∘c. the density of the solvent at that temperature is 0.997 g/ml. calculate the mole percent of cacl2 in the solution.

Mole percent of in solution is 1.71%

Explanation:

Number of moles of a compound is the ratio of mass to molar mass of the compound.

Molar mass of = 110.98 g/mol

Molar mass of = 18.02 g/mol

Density is the ratio of mass to volume

So, mass of 60.0 mL of water =

Hence, 6.50 g of = of = 0.0586 moles of

60.8 g of = of = 3.37 moles of

So, mole percent of in solution = \frac{n_{CaCl_{2}}}{n_{total}}\times 100% = % = 1.71%