What volume of carbon dioxide is produced when 0.489 mol of calcium carbonate reacts completely according to the following reaction at 0°c and 1 atm? calcium carbonate ( s ) calcium oxide ( s ) + carbon dioxide ( g )

11.0L of carbon dioxide is produced

Explanation:

Balanced equation:

According to balanced equation, 1 mol of produces 1 mol of

So, 0.489 mol of produces 0.489 mol of

Let's assume behaves ideally.

So,

where P is pressure, V is volume , n is number of moles, R is gas constant and T is temperature in kelvin

Plug-in all the values in the above equation-

or,

So, 11.0L of carbon dioxide is produced