A115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.
what is the percent yield of oxygen in this chemical reaction?

The balanced chemical reaction will be:

2KClO3 = 2KCl + 3O2

We are given the amount of potassium chlorate being burned. This will be our starting point.

400.0 g KClO3 1 mol  KClO3/ 122.55  g KClO3) (3 mol O2/2 mol KClO3) ( 32.00 g O2/1mol O2) = 156.67 g O2

Percent yield = actual yield / theoretical yield x 100

Percent yield =115.0 g / 156.67  g x 100

Percent yield = 73.40 %

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter