How many grams of chlorine gas are needed to make 117 grams of sodium chloride? given the reaction: 2na + cl2 → 2nacl

The mass of chlorine gas, Cl₂ needed to make 117 g of sodium chloride, NaCl is 71 g

We'll begin by calculating the mass of Cl₂ that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:

2Na + Cl₂ → 2NaCl

Molar mass of Cl₂ = 2× 35.5 = 71 g/mol

Mass of Cl₂ from the balanced equation = 1 × 71 = 71 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g

From the balanced equation above,

71 g of Cl₂ reacted to produce 117 g of NaCl.

Thus, we can conclude that 71 g of chlorine gas, Cl₂ is needed to make 117 g of sodium chloride, NaCl.

Learn more: link

71 grams of chlorine gas.

Explanation:

2Na + Cl2 = 2NaCl.

From the molar masses:

2(23+35.45) g of NaCl are made from  2*35.45 g Cl2 gas.

So  117 g are made from  (2*35.45  * 117)  / 2(23+35.45)

= 71 g.

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023