Calculate the number of atoms of each type in c12h22o11 and record

1 mol of sucarose has 7.22 x10²⁴ atoms of C, 1.32 x10²⁵ atoms of H and 6.62 x10²⁴ atoms of O

Explanation:

C12H22O11 is the molecular formular for sucarose

So in 1 mol of sacarose, we have 12 mols of carbon, 22 moles of hydrogen, and 11 mols of oxygen.

As you know, 1 mol has 6.02x10²³ atoms so these are the rule of three to calculate the number of atoms of each type.

1 mol 6.02x10²³

12 moles 12 . 6.02x10²³ = 7.22 x10²⁴

22 moles 22 . 6.02x10²³ = 1.32 x10²⁵

11 moles 11 . 6.02x10²³ = 6.62 x10²⁴

it's c. elements are placed in rows based on how may valencies electrons have.