The reaction: 2 so2(g) + o2(g) --> 2 so3(g) has an equilibrium constant of k1. what is the k value for the reaction: so3(g) --> so2(g) + ½ o2(g)?

k1^½
1/k1
½ k1
(1/k1)^½

The value of equilibrium constant for reverse reaction is

Explanation:

The given chemical equation follows:

The equilibrium constant for the above equation is

We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant  of initial reaction.

The value of equilibrium constant for reverse reaction is:

Hence, the value of equilibrium constant for reverse reaction is

these nuts

the answer would be b i believe