Using the standard enthalpies of formation for the chemicals involved, calculate the enthalpy change for the following reaction.

(note: show the math clearly and provide units in your set up) ( hf values in kj/mol are as follows: no2 32, h2o 286, hno3 207, no 90.)

3no2(g) h2o(l) 2hno3(aq) no(g) g

-134 kJ

Explanation:

The balanced chemical reaction is,

The expression for enthalpy change is,

where,

n = number of moles

Now put all the given values in this expression, we get

Therefore, the enthalpy change for this reaction is, -134 kJ

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