Consider a solution containing 0.181 m lead (ii) ions and 0.174 m mercury(ii) ions. calculate the maximum concentration of sulfide ions that can be in solution without precipitating any lead ions. ksp: lead sulfide is 3.4 × 10−28; mercury(ii) sulfide is 4.0 × 10−53.

In a copper wire, a temperature increase is the result of which of the following

Given the following at 25c calculate delta hf for hcn (g) at 25c. 2nh3 (g) +3o2 (g) + 2ch4 (g) > 2hcn (g) + 6h2o (g) delta h rxn= -870.8 kj. delta hf=-80.3 kj/mol for nh3 (g), -74.6 kj/mol for ch4, and -241.8 kj/mol for h2o (g)

Phosphorous can form an ion called phosphide, which has the formula p3−. this ion can form an ion called phosphide, which has the formula p3−. this ion properties very similar to those of pforms when a phosphorus atom loses three protonsis called a cationcontains 18 electrons